-16x^2+144x+20=0

Solution for -16x^2+144x+20=0 equation:

-16x^2+144x+20=0

a = -16; b = 144; c = +20;
Δ = b2-4ac
Δ = 1442-4·(-16)·20
Δ = 22016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22016}=\sqrt{256*86}=\sqrt{256}*\sqrt{86}=16\sqrt{86}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-16\sqrt{86}}{2*-16}=\frac{-144-16\sqrt{86}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+16\sqrt{86}}{2*-16}=\frac{-144+16\sqrt{86}}{-32}
$